Brunston
Saturday, 17 August 2013
Group presentations and subgroups
Group presentations and subgroups
How to prove that $G=\langle a,b,c\mid a^2 = b^2 = c^3 = 1, ab = ba,
cac^{-1} = b, cbc^{-1} =ab\rangle$ has no subgroup of order $6$ without
finding $G$?
No comments:
Post a Comment
Newer Post
Older Post
Home
Subscribe to:
Post Comments (Atom)
No comments:
Post a Comment